document.write( "Question 757744: A rectangular portrait is 3 inches longer than it is wide. A 3 inch frame of uniform width is to be placed around the portrait. The area of the portrait and frame is 108in^2. Find the dimensions of the portrait without the frame. \n" ); document.write( "
Algebra.Com's Answer #461068 by sachi(548)![]() ![]() You can put this solution on YOUR website! letbthe width is x\" then the length is x+3\" \n" ); document.write( "A 3 inch frame of uniform width is to be placed around the portrait i.e on both length & width will increase by 3\" \n" ); document.write( "so the dimension of the portrait with frame will be L=x+3+3\" & W=x+3\" \n" ); document.write( "so the area=(x+3)(x+6)=108 \n" ); document.write( "or x^2+9x+18=108 \n" ); document.write( "or x^2+9x-90=0 \n" ); document.write( "or x^2+15x-6x-90=0 \n" ); document.write( "or x(x+15)-6(x+15)=0 \n" ); document.write( "or (x+15)(x-6)=0 \n" ); document.write( "or x=6 or -15 \n" ); document.write( "so x= 6 rejecting -ve value \n" ); document.write( "so the dimensions of the portrait without the frame w=6\" & l=6+3=9\" \n" ); document.write( " |