document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757732>Question 757732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 inches longer than the width. If the area is 315 square inches, find the rectangle's dimensions. Round your answers to the nearest tenth of an inch.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #461049 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=461049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 inches longer than the width. If the area is 315 square inches, find the rectangle's dimensions. Round your answers to the nearest tenth of an inch.\r<BR>\n" );
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document.write( "Let x be the length then the width is (x - 2).\r<BR>\n" );
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document.write( "The area is A = Length * Width = x(x - 2) = 315\r<BR>\n" );
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document.write( "x^2 - 2x - 315 = 0\r<BR>\n" );
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document.write( "Solve for x (length). From there, you can find the width.\r<BR>\n" );
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document.write( "Hope it helps! John\r<BR>\n" );
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