document.write( "Question 757322: Ron and pat leaves for the beach at the same point. Ron leaves first pat leaves 45 mins later traveling 10 mph faster then Ron. pat passes ron 4 hours later. find the rate of each driver. \n" ); document.write( "
Algebra.Com's Answer #461027 by ankor@dixie-net.com(22740)\"\" \"About 
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Ron and pat leaves for the beach at the same point.
\n" ); document.write( " Ron leaves first, Pat leaves 45 mins later traveling 10 mph faster
\n" ); document.write( " than Ron.
\n" ); document.write( "Pat passes Ron 4 hours later. find the rate of each driver.
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\n" ); document.write( "Since we a dealing in hrs here, convert 45 min to .75 hrs
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\n" ); document.write( "From the information given, we know
\n" ); document.write( "P's travel time = 4 hrs
\n" ); document.write( "R's travel time = 4.75 hrs
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\n" ); document.write( "let s = R's rate
\n" ); document.write( "then
\n" ); document.write( "(s+10) = P's rate
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\n" ); document.write( "When P catches R, they will have traveled the same distance.
\n" ); document.write( "Write a distance equation; Dist = time * speed
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\n" ); document.write( "R's dist = P's dist
\n" ); document.write( " 4.75s = 4(s+10)
\n" ); document.write( " 4.75s = 4s + 40
\n" ); document.write( " 4.75s - 4s = 40
\n" ); document.write( " .75s = 40
\n" ); document.write( " s = 40/.75
\n" ); document.write( " s = 53\"1%2F3\" mph is R's rate
\n" ); document.write( "then
\n" ); document.write( " 53\"1%2F3\" + 10 = 63\"1%2F3\" mph is P's rate
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\n" ); document.write( "You can check this out for yourself, determine the distance each
\n" ); document.write( "traveled, should be the same. (dist = rate * time) \r
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