document.write( "Question 757654: A boy counts toads at 22/min and then frogs at 18/min. He counts for a total of 4 mins and realizes that he has counted an equal number of toads and frogs. How long did he count toads?\r
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document.write( "I know he counted frogs longer because they are slower. I know he counted toads at 4/min faster.\r
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Algebra.Com's Answer #460983 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! That's an interesting new uniform-rates problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So there were counting reptiles. Each reptile is counted at a different rate. r*t=q using r for rate in reptile per minute, t is time in minutes, q is the count of reptiles whether frog or toad. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which Reptile_______________rate______________time_____________count \n" ); document.write( "TOADS_______________________22________________(___)____________q \n" ); document.write( "FROGS_______________________18________________(___)____________q\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We only know that q is the same for both kinds. We know the total time counting was 4 minutes but not yet how much time for each kind of reptile. We can make expressions for each.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Which Reptile_______________rate______________time_____________count \n" ); document.write( "TOADS_______________________22________________(q/22)____________q \n" ); document.write( "FROGS_______________________18________________(q/18)____________q \n" ); document.write( "Total_________________________________________4_________________2q\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We use the found equation of \n" ); document.write( " \n" ); document.write( " |