document.write( "Question 757654: A boy counts toads at 22/min and then frogs at 18/min. He counts for a total of 4 mins and realizes that he has counted an equal number of toads and frogs. How long did he count toads?\r
\n" ); document.write( "\n" ); document.write( "I know he counted frogs longer because they are slower. I know he counted toads at 4/min faster.\r
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Algebra.Com's Answer #460983 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
That's an interesting new uniform-rates problem.\r
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\n" ); document.write( "\n" ); document.write( "So there were counting reptiles. Each reptile is counted at a different rate. r*t=q using r for rate in reptile per minute, t is time in minutes, q is the count of reptiles whether frog or toad. \r
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\n" ); document.write( "\n" ); document.write( "Which Reptile_______________rate______________time_____________count
\n" ); document.write( "TOADS_______________________22________________(___)____________q
\n" ); document.write( "FROGS_______________________18________________(___)____________q\r
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\n" ); document.write( "\n" ); document.write( "We only know that q is the same for both kinds. We know the total time counting was 4 minutes but not yet how much time for each kind of reptile. We can make expressions for each.\r
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\n" ); document.write( "\n" ); document.write( "Which Reptile_______________rate______________time_____________count
\n" ); document.write( "TOADS_______________________22________________(q/22)____________q
\n" ); document.write( "FROGS_______________________18________________(q/18)____________q
\n" ); document.write( "Total_________________________________________4_________________2q\r
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\n" ); document.write( "\n" ); document.write( "We use the found equation of \"highlight%28q%2F22%2Bq%2F18=4%29\" and solve for q. You can easily compute the time for the counting of each reptile, just using the time expression as shown. Remember, q is for the number of each reptile counted.
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