document.write( "Question 757595: Find exact value of tan(arcsec 17÷15 - cot -3÷4) \n" ); document.write( "
Algebra.Com's Answer #460982 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Find exact value of tan(arcsec 17÷15 - cot -3÷4) \n" ); document.write( "*** \n" ); document.write( "let sec(x)=17/15 \n" ); document.write( "Identity: \n" ); document.write( " \n" ); document.write( "tan(x)=8/15 \n" ); document.write( ".. \n" ); document.write( "let cot(y)=-3/4 \n" ); document.write( "tan(y)=-4/3 \n" ); document.write( ".. \n" ); document.write( "tan(arcsec 17÷15 - cot -3÷4)=tan(x-y) \n" ); document.write( "Identity: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "tan(arcsec 17÷15 - cot -3÷4)=84/13 \n" ); document.write( ".. \n" ); document.write( "calculator check: \n" ); document.write( "cos(x)=15/17 \n" ); document.write( "x≈28.07º \n" ); document.write( "tan(y)=-4/3 \n" ); document.write( "y≈126.87º (in Q2 where tan<0) \n" ); document.write( "x-y=28.07-126.87≈-98.8º (in Q3 where tan>0) \n" ); document.write( "tan(x-y)=tan(-98.8º)≈6.46 \n" ); document.write( "exact value=84/13≈6.46 \n" ); document.write( " |