document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757645>Question 757645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I made a big typo with my last question... \r<BR>\n" );
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document.write( "\"The owner of a deli mixed coffee that cost $9/lbwith coffee that cost $6/lb. How many lbs of each were used to make a 20lb mixture costing $7.80/lb.\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460960 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a = the number of lbs of the $9/lb coffee<BR>\n" );
document.write( "Since there are 20 lbs in the mixture, the number of lbs of the $6/lb coffee will be 20 - a<BR>\n" );
document.write( "Adding up the total dollar amount of the two coffees and equating that to the total in the mixture gives<BR>\n" );
document.write( "9a + 6(20-a) = 7.80*20<BR>\n" );
document.write( "Solve for a:<BR>\n" );
document.write( "9a + 120 - 6a = 156<BR>\n" );
document.write( "3a = 36<BR>\n" );
document.write( "a = 12<BR>\n" );
document.write( "So there are 12 lbs of the $9 coffee and 8 lbs of the $6 coffee </SPAN>\n" );
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