document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757614>Question 757614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The probability that a slightly defective soda machine will dispense a soda when properly operated is 0.60. During the day 150 people attempted to use the machine to purchase a soda.\r<BR>\n" );
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document.write( "a. What is the expected number of these people who obtain a soda from this machine?\r<BR>\n" );
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document.write( "b. With what standard deviation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460959 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a binomial probability problem, where the expected number is given by the mean.  The mean of a binomial distribution = n*p where n = the number of trials and p = the probability of success in any one trial.<BR>\n" );
document.write( "Expected value = 150*0.6 = 90<BR>\n" );
document.write( "The standard deviation = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28np%281-p%29%29+=+sqrt%28150%2A0.6%2A0.4%29+=+6 ALIGN=MIDDLE  ALT=\"sqrt%28np%281-p%29%29+=+sqrt%28150%2A0.6%2A0.4%29+=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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