document.write( "Question 757632: The perimeter of a rectangle is 146 inches. The length is 7 inches shorter than three times the width. Find the length \r
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Algebra.Com's Answer #460957 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The perimeter of a rectangle is \"146in\". \r
\n" ); document.write( "\n" ); document.write( "The length is \"L=3W-7in\" (if \"7in\" shorter than three times the width)\r
\n" ); document.write( "\n" ); document.write( "\"P=2L%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "\"2L%2B2W=146in\".....simplify, all terms divide by \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2BW=73in\".......eq.1 substitute \"L=3W-7in\"\r
\n" ); document.write( "\n" ); document.write( "\"3W-7in%2BW=73in\"\r
\n" ); document.write( "\n" ); document.write( "\"4W=73in%2B7in\"\r
\n" ); document.write( "\n" ); document.write( "\"4W=80in\"\r
\n" ); document.write( "\n" ); document.write( "\"W=80in%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28W=20in%29\"\r
\n" ); document.write( "\n" ); document.write( "now find \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"L=3%2A20in-7in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=60in-7in\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28L=53in%29\"\r
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