document.write( "Question 757408: In △JKL, solve for x. \r
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document.write( "Triangle JKL where angle K is a right angle. KL measures 34; JL measures x; angle J measures 27 degrees. \n" );
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Algebra.Com's Answer #460908 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Trigonometric ratio. \n" ); document.write( "Sin = Opposite/ Hypotenuse \n" ); document.write( "sin 27 = 34/x \n" ); document.write( "Cross multiply \n" ); document.write( "x = 34/sin 27 \n" ); document.write( "x = 74.9 \n" ); document.write( "Hope this helps \n" ); document.write( ":-) \n" ); document.write( " |