document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4028>Question 4028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x+1)^(-3/2)=8\r<BR>\n" );
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document.write( "Solve the complex solution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460905 by </B><A HREF=/tutors/aboutme.mpl?userid=tangled_mind><B>tangled_mind(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tangled_mind><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+1)^(-3/2)=8<BR>\n" );
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document.write( "to put (-3/2) down multiply both sides with ln\r<BR>\n" );
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document.write( "ln{(x+1)^(-3/2)}=ln{8}<BR>\n" );
document.write( "(-3/2) ln (x+1) = ln 8<BR>\n" );
document.write( "(-3/2)(lnx + ln1) = ln 8<BR>\n" );
document.write( "ln x = (ln 8 + (3/2)(ln 1))(-2/3)<BR>\n" );
document.write( "e^(ln x) = e^((ln 8 + (3/2)(ln 1))(-2/3))<BR>\n" );
document.write( "x=(8+(3/2))(-2/3)<BR>\n" );
document.write( "x = -19/3 or -6.33333 </SPAN>\n" );
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