document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757426>Question 757426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 200 yards. what are the dimensions of the rectangle if the length is 40 yards more than the width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460896 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2*length + 2*width<BR>\n" );
document.write( "Perimeter = 2*(x + 40) + 2x<BR>\n" );
document.write( "200yds    = 2x + 80 + 2x<BR>\n" );
document.write( "      4x + 80 = 200<BR>\n" );
document.write( "            4x = 200 - 80<BR>\n" );
document.write( "            4x = 120<BR>\n" );
document.write( "             x = 30.<BR>\n" );
document.write( "Length = 70yds<BR>\n" );
document.write( "Width = 30yds<BR>\n" );
document.write( "Perimeter = 2*length + 2*width<BR>\n" );
document.write( "          = 2*70 + 2*30<BR>\n" );
document.write( "          = 200yds.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-)<BR>\n" );
document.write( "     </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );