document.write( "Question 757472: A real estate salesperson bought promotional calendars and date books to give to her customers at the end of the year. The calendars cost $0.75 each, and the date books cost $0.50 each. She ordered a total of 500 promotional items and spent $300. How many of each item did she order? \n" ); document.write( "

Algebra.Com's Answer #460880 by Cromlix(4381) $\"\"$ $\"About$

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Calendars = x
\n" ); document.write( "Books = y
\n" ); document.write( " x + y = 500........1
\n" ); document.write( "75x + 50y = 30000......2
\n" ); document.write( "Multiply (1) by 50
\n" ); document.write( " 50x + 50y = 25000.....3
\n" ); document.write( " 75x + 50y = 30000.....2
\n" ); document.write( "Subtract (3) from (2)
\n" ); document.write( " 25x = 5000
\n" ); document.write( "Divide both sides by 25
\n" ); document.write( " x = 200
\n" ); document.write( "Substitute x = 200 in
\n" ); document.write( "Eq(1)
\n" ); document.write( " x + y = 500
\n" ); document.write( "200 + y = 500
\n" ); document.write( " y = 500 - 200
\n" ); document.write( " y = 300
\n" ); document.write( "Therefore, the salesperson ordered
\n" ); document.write( "200 calendars and 300 date books.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "

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