document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65433>Question 65433</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Find a :\r<BR>\n" );
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document.write( "4x / 2y + 3a - p = c/q </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46082 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find a : <BR>\n" );
document.write( "4x / 2y + 3a - p = c/q  First, subtract 4x/2y from both sides\r<BR>\n" );
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document.write( "4x/2y-4x/2y+3a-p=c/q-4x/2y and we get:\r<BR>\n" );
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document.write( "3a-p=c/q-4x/2y  Next, add p to both sides\r<BR>\n" );
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document.write( "3a-p+p=c/q-4x/2y+p and we get:<BR>\n" );
document.write( "3a=c/q-4x/2y+p Before we go further, lets simplify the right side by multiplying every term by 2yq/2yq   (2yq is the lowest common multiple.  Doing this will give us a common denominator)\r<BR>\n" );
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document.write( "3a=(c/q)(2yq/2yq)-(4x/2y)(2yq/2yq)+(p)(2yq/2yq) simplifying\r<BR>\n" );
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document.write( "3a=((2cy)-(4xq)+(2pqy))/2yq\r<BR>\n" );
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document.write( "a=((2cy)-(4xq)+(2pqy))/6yq  Now multiply right side by 2/2\r<BR>\n" );
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document.write( "a=((cy)-(2qx)+(pqy))/2qy\r<BR>\n" );
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document.write( "Happy holidays----ptaylor </SPAN>\n" );
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