document.write( "Question 757384: Vehicle A which is ahead of vehicle B by 2/3 mile is traveling at 53 mph. Vehicle B which is behind vehicle A is traveling 75 mph. How long and how far will it take vehicle B to catch vehicle A?\r
\n" ); document.write( "\n" ); document.write( "Same question but with A going 30 mph.
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Algebra.Com's Answer #460808 by lwsshak3(11628)\"\" \"About 
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Vehicle A which is ahead of vehicle B by 2/3 mile is traveling at 53 mph. Vehicle B which is behind vehicle A is traveling 75 mph. How long and how far will it take vehicle B to catch vehicle A?
\n" ); document.write( "Same question but with A going 30 mph.
\n" ); document.write( "***
\n" ); document.write( "let x=distance A traveled
\n" ); document.write( "x+2/3=distance B traveled to catch A
\n" ); document.write( "travel time=distance/speed (same for A and B)
\n" ); document.write( "..
\n" ); document.write( "\"x%2F53=%28x%2B2%2F3%29%2F75\"
\n" ); document.write( "75x=53x+(106/3
\n" ); document.write( "22x=106/3
\n" ); document.write( "x=106/66
\n" ); document.write( "x≈1.6
\n" ); document.write( "x+2/3≈2.27
\n" ); document.write( "travel time=1.6/53=.03 hr or≈1.81 min
\n" ); document.write( "B will catch up to A in 1.81 min after traveling 2.27 mi
\n" ); document.write( "..
\n" ); document.write( "For A going 30 mph
\n" ); document.write( "\"x%2F30=%28x%2B2%2F3%29%2F75\"
\n" ); document.write( "75x=30x+20
\n" ); document.write( "45x=20
\n" ); document.write( "x=20/45
\n" ); document.write( "x≈0.44
\n" ); document.write( "x+2/3≈1.11
\n" ); document.write( "travel time=0.44/30=.015hr or≈0.89 min
\n" ); document.write( "B will catch up to A in 0.89 min after traveling 1.11mi
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