document.write( "Question 757382: Can you explain how to solve logarithmic expressions so that they are single logarithms?
\n" ); document.write( "Example:
\n" ); document.write( "How would you solve:
\n" ); document.write( "log 15+ log 8 as a single expression.
\n" ); document.write( "

Algebra.Com's Answer #460773 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The rule is:
\n" ); document.write( "\"+log%28a%29+%2B+log%28b%29+=+log%28%28+a%2Ab+%29%29+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "You can see this very well if you use
\n" ); document.write( "logs to the base \"+10+\"
\n" ); document.write( "-------------
\n" ); document.write( "Suppose the equation is:
\n" ); document.write( "\"+log%28+10000+%29+%2B+log%28+100000000+%29+\"
\n" ); document.write( "which is
\n" ); document.write( "\"+log%28+10%5E4+%29+%2B+log%28+10%5E8+%29+\"
\n" ); document.write( "\"+4+%2B+8+=+12+\"
\n" ); document.write( "---------------
\n" ); document.write( "Applying the rule:
\n" ); document.write( "\"+log%28+10%5E4+%29+%2B+log%28+10%5E8+%29+=+log%28%28+10%5E4+%2A+10%5E8+%29%29+\"
\n" ); document.write( "\"+log%28+10%5E4+%2A+10%5E8+%29+=+log%28+10%5E12+%29+\"
\n" ); document.write( "and
\n" ); document.write( "\"+log%28+10%5E12+=+12+%29+\"
\n" ); document.write( "so, the rule works.
\n" ); document.write( "In words, the rule says, \" Add the logs of 2 numbers
\n" ); document.write( "and you will get the
\n" ); document.write( "same result if you multiply the 2 numbers
\n" ); document.write( "themselves and then take the log of that product.
\n" ); document.write( "Hope this helps\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );