document.write( "Question 757302: a person plans to invest four times as much in an account at 6% interest as in an account at 9% annual interest. how much should the person invest in each account to earn a total of $825 in one year? \n" ); document.write( "
Algebra.Com's Answer #460742 by LearnWithMajor(33)\"\" \"About 
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x = investment at 6% interest. y = investment at 9% interest\r
\n" ); document.write( "\n" ); document.write( "simple interest equation: interest = principle*rate*time(years)
\n" ); document.write( "i = p*r*t\r
\n" ); document.write( "\n" ); document.write( "a person plans to invest four times as much in 6% as in 9%
\n" ); document.write( "x = 4y\r
\n" ); document.write( "\n" ); document.write( "the person wants to earn a total of $825 in interest in 1 year so when we add the interest from both accounts it should equal 825. \r
\n" ); document.write( "\n" ); document.write( "0.06x + 0.09y = 825\r
\n" ); document.write( "\n" ); document.write( "Substituting 4y in for x we get
\n" ); document.write( "0.06(4y) + 0.09y = 825
\n" ); document.write( "0.24y + 0.09y = 825
\n" ); document.write( "0.33y = 825
\n" ); document.write( "y = 825/0.33 = 2500
\n" ); document.write( "x = 4y = 4(2500) = 10000
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