document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757215>Question 757215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve 3 sec^2 theta + 5 sec theta + 2 = 0?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460719 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How to solve 3 sec^2 theta + 5 sec theta + 2 = 0?<BR>\n" );
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document.write( "For simplicity, I will replace theta with x.<BR>\n" );
document.write( "Since sec x = 1/cos x we can write<BR>\n" );
document.write( "3/cos^2(x) + 5/cos(x) + 2 = 0<BR>\n" );
document.write( "Multiply through by cos^2(x):<BR>\n" );
document.write( "2cos^2(x) + 5cos(x) + 3 = 0<BR>\n" );
document.write( "This can be factored as<BR>\n" );
document.write( "(2cos(x)+3)(cos(x)+1) = 0<BR>\n" );
document.write( "The solutions are cos(x) = -1 and cos(x) = -3/2<BR>\n" );
document.write( "Since the magnitude of cos(x) can not be > 1, we discard the 2nd solution.<BR>\n" );
document.write( "This gives x = n*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > where n=integer<BR>\n" );
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