document.write( "Question 757191: This question is based on grad 12, Calculus
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document.write( "a bacteria colony has a mass that varies with time.The original mass of the bacteria is 20 g and the mass increases by 50% eache day\r
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document.write( "a) write an equation to model the growth of the mass of the colony
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document.write( "b) what is the intial rate of change of the mass of the colony?
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document.write( "c) During which day is the mass of the colony increasing by 60 g/day?
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document.write( "d) When will the mass of the colony be 60 Kg? \n" );
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Algebra.Com's Answer #460702 by KMST(5328)![]() ![]() You can put this solution on YOUR website! The mass of the colony increases by a factor of 1.5 each day, \n" ); document.write( "so if \n" ); document.write( "and \n" ); document.write( "we could write \n" ); document.write( "However, it is traditional (and more convenient when calculating derivatives) to use \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "b) The rate of change of the mass of the colony would be the derivative of \n" ); document.write( " \n" ); document.write( "Fot \n" ); document.write( " \n" ); document.write( "c) During which day is the mass of the colony increasing by 60 g/day? \n" ); document.write( "we need to find the value of \n" ); document.write( " \n" ); document.write( "I would call that time (and any time \n" ); document.write( " \n" ); document.write( "d) When will the mass of the colony be 60 Kg? \n" ); document.write( "60Kg is a lot. It's 60,000 grams. \n" ); document.write( " \n" ); document.write( "So, in the ideal world of math, it would take 20 days to get 60 kg of bacteria. \n" ); document.write( " \n" ); document.write( "In real life, a colony would not keep growing at the same rate for that long. Even with a lot of attention, \"feeding\", and \"transplanting\", grow would not stay constant. \n" ); document.write( " |