document.write( "Question 757198: Find the binominal distribution for which the mean is 4 and variance is 3 \n" ); document.write( "
Algebra.Com's Answer #460696 by reviewermath(1029)![]() ![]() You can put this solution on YOUR website! Q: \n" ); document.write( "Find the binominal distribution for which the mean is 4 and variance is 3 \n" ); document.write( "------------------------------------------------------------------ \n" ); document.write( "A: \n" ); document.write( "If X~Binomial(n, p), then \n" ); document.write( "Mean, E(X) = np and \n" ); document.write( "Variance, Var(X) = npq \n" ); document.write( "np = 4 and npq = 3 \n" ); document.write( "Therefore, npq/np = 3/4 = 0.75 OR \n" ); document.write( "q = 0.75 \n" ); document.write( "p = 1 - q = 1 - 0.75 = 0.25 \n" ); document.write( "0.25n = 4 so n = 16 \n" ); document.write( "n = 16 and p = 0.25 \n" ); document.write( "X~Binomial(16, 0.25) \n" ); document.write( "P(X = x) = \n" ); document.write( " \n" ); document.write( " |