document.write( "Question 757198: Find the binominal distribution for which the mean is 4 and variance is 3 \n" ); document.write( "
Algebra.Com's Answer #460696 by reviewermath(1029)\"\" \"About 
You can put this solution on YOUR website!
Q:
\n" ); document.write( "Find the binominal distribution for which the mean is 4 and variance is 3
\n" ); document.write( "------------------------------------------------------------------
\n" ); document.write( "A:
\n" ); document.write( "If X~Binomial(n, p), then
\n" ); document.write( "Mean, E(X) = np and
\n" ); document.write( "Variance, Var(X) = npq
\n" ); document.write( "np = 4 and npq = 3
\n" ); document.write( "Therefore, npq/np = 3/4 = 0.75 OR
\n" ); document.write( "q = 0.75
\n" ); document.write( "p = 1 - q = 1 - 0.75 = 0.25
\n" ); document.write( "0.25n = 4 so n = 16
\n" ); document.write( "n = 16 and p = 0.25
\n" ); document.write( "X~Binomial(16, 0.25)
\n" ); document.write( "P(X = x) = \"%28matrix%282%2C1%2C16%2Cx%29%29%280.25%5Ex%29%280.75%5E%2816+-+x%29%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );