document.write( "Question 757169: three squares have sides with lengths a,b and c. if b is 20%greater than a, c is 25%greater than b, then by what percent is the area of the largest square greater than the area of the smallest square \n" ); document.write( "
Algebra.Com's Answer #460682 by sachi(548)![]() ![]() You can put this solution on YOUR website! three squares have sides with lengths a,b and c. \n" ); document.write( "if b is 20%greater than a, c is 25%greater than b, \n" ); document.write( "so b=a+20%a=1.2a \n" ); document.write( "& c=b+25%b=1.25b=1.25*1.2a=1.5a \n" ); document.write( "so the sides of the 3 squares are a,1.2a & 1.5a \n" ); document.write( "now it is clear that greatest square is of sides 1.5a & smallest is of a \n" ); document.write( "so the areas are (1.5a)^2=2.25a^2 & a^2 \n" ); document.write( "the percent difference in the area of the largest square & the smallest square \n" ); document.write( "=(2.25a^2-a^2)*100/a^2=(2.25-1)*100=125% \n" ); document.write( " |