document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757170>Question 757170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Samuel is 2/3 as old as his brother.  In five years, he will be 3/4 as old as his brother will be.  Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460681 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let samuel's  brother is x yrs<BR>\n" );
document.write( "then samuel is 2x/3 yrs<BR>\n" );
document.write( "after 5 yrs samuel will be 2x/3+5 & his brother will be x+5<BR>\n" );
document.write( "he will be 3/4 as old as his brother will be<BR>\n" );
document.write( "so 2x/3+5=3(x+5)/4<BR>\n" );
document.write( "or 8x+60=9x+45 multiplying 12 both sides<BR>\n" );
document.write( "or x=15<BR>\n" );
document.write( "so samuel's  brother is 15 yrs & samuel 2*15/3=10 yrs<BR>\n" );
document.write( " </SPAN>\n" );
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