document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757164>Question 757164</A>: <I><SPAN STYLE=\"word-break: break-all;\"> identify the center and the radius of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%5E2+%2B+%28y-1%29%5E2=9 ALIGN=MIDDLE  ALT=\"%28x-2%29%5E2+%2B+%28y-1%29%5E2=9\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460666 by </B><A HREF=/tutors/aboutme.mpl?userid=LearnWithMajor><B>LearnWithMajor(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LearnWithMajor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This equation has the standard form of a circle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where (h,k) is the center of the circle and r is the radius of the circle. \r<BR>\n" );
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document.write( "Therefore for our above equation h = 2, k = 1, and r^2 = 9. Taking the positive squareroot of 9 we get that r = 3. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt%289%29+=+3+ ALIGN=MIDDLE  ALT=\"+sqrt%289%29+=+3+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The center of the circle is at (2,1) and the radius of the circle is 3. </SPAN>\n" );
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