document.write( "Question 756283: identify the focus and directrix of the parabola given by \"+y%5E2+=+-4x+\" \n" ); document.write( "
Algebra.Com's Answer #460653 by lwsshak3(11628)\"\" \"About 
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identify the focus and directrix of the parabola given by \"+y%5E2+=+-4x+\"
\n" ); document.write( "Given parabola opens leftward:
\n" ); document.write( "Its basic equation: y^2=-4px
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: y=0 or x-axis
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "focus: (-1,0) (p-distance to left of vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=1 (p-distance to right of vertex on the axis of symmetry)
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