document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757049>Question 757049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter of a triangle if one side is 5 centimeters, another side is three-sevenths the perimeter, and the third side is one-half the perimeter.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460590 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let p = the perimeter of the triangle<BR>\n" );
document.write( "Since the perimeter is the sum of the three side we get from the problem statement,<BR>\n" );
document.write( "(1) p = 5 + (3/7)*p + (1/2)*p or<BR>\n" );
document.write( "(2) p*(1 - (3/7) - (1/2)) = 5 or<BR>\n" );
document.write( "(3) p*(14 - 7 -6) = 14*5 or<BR>\n" );
document.write( "(4) p = 70<BR>\n" );
document.write( "Let's check this using (1),<BR>\n" );
document.write( "Is (70 = 5 + (3/7)*70 + (1/2)*70)?<BR>\n" );
document.write( "Is (70 = 5 + 30 + 35)?<BR>\n" );
document.write( "Is (70 = 70)? Yes<BR>\n" );
document.write( "Answer: The perimeter of the triangle is 70 cm. </SPAN>\n" );
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