document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65510>Question 65510</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534944949/algebrahomeworkh>Essential Algebra</A><BR>\n" );
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document.write( "Mr and Mrs Morales agree to meet at 3:00pm at Los Alamos, a town between their present locations. They both leave their present location at 10:45am. Mr Morales drives at an average speed of 50 kph to arrive on time.\r<BR>\n" );
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document.write( "a) If Mrs Morales must drive 34 kilometers further than Mr Morales, what must her average speed be to arrive on time?\r<BR>\n" );
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document.write( "b) How far will Mr and Mrs Morales have driven when they meet in Los Alamos? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46054 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE TIME REQUIRED BY MR MORALES TO DRIVE IS 4.25 HOURS (10:45 AM TO 3:00 PM)<BR>\n" );
document.write( "50*4.25=212.5 KILOMETERS DRIVEN BY MR MORALES.<BR>\n" );
document.write( "MRS MORALES MUST DRIVE 212.5+43=255.5 KILOMETERS. SO SHE MUST DRIVE 255.5 KILOMETERS IN 4.25 HOURS. THUS:<BR>\n" );
document.write( "255.5/4.25=X<BR>\n" );
document.write( "X=60.118 KILOMETERS PER HOUR SHE MUST DRIVE TO ARRIVE ON TIME.<BR>\n" );
document.write( "TOTAL DISTANCE DRIVEN BY MR & MRS MORALES. 212.5+255.5=468 KILOMETERS.<BR>\n" );
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document.write( "MERRY CHRISTMAS </SPAN>\n" );
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