document.write( "Question 756988: If someone 50% of their cereal 20% of their fruit 15% of their milk and 15% of their juice how much did they eat total \n" ); document.write( "
Algebra.Com's Answer #460538 by dkppathak(439)\"\" \"About 
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50% of their cereal =50/100=1/2 part LEFT =1/2 part
\n" ); document.write( "20% of their fruit =20/100 =1/5 part LEFT=4/5 part\r
\n" ); document.write( "\n" ); document.write( "15% of their milk =15/100 =3/20 part LEFT=17/20 part
\n" ); document.write( "and
\n" ); document.write( "15% of their juice =15/100=3/20 part LEFT=17/20 part
\n" ); document.write( "how much did they eat total
\n" ); document.write( " total eat=1/2+1/5+3/20+3/20 by LCM LEFT =1/2+4/5+17/20+17/20 part
\n" ); document.write( " =10+4+3+3/20
\n" ); document.write( " =20/20=1 PART CONSUMED LEFT PART =10+16+17+17/20
\n" ); document.write( " =60/20 part
\n" ); document.write( "CONSUMED PART=1 LEFT PART =3 PART
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\n" ); document.write( "TOTAL EAT PART =1/4 LEFT PART =3/4
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