document.write( "Question 756942: the area of a rectangular field is 900 sq.m. if the length be diminished by 6m and breadth be increased by 5m it becomes a square. find the perimeter of the rectangular field \n" ); document.write( "
Algebra.Com's Answer #460524 by ptaylor(2198)\"\" \"About 
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Area of rectangle (A) equals length(L) times width(W) or A=LW
\n" ); document.write( "Let L be the length of rectangle
\n" ); document.write( "and Let W be the width
\n" ); document.write( "Sooo, A=LW=900 sq m.----------------------eq1
\n" ); document.write( "Length diminished by 6m=L-6
\n" ); document.write( "Width increased by 5m=W+5\r
\n" ); document.write( "\n" ); document.write( "Now we know that the length and width of a square are equal, so:
\n" ); document.write( "L-6=W+5---------------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "From eq 1, W=900/L; substitute this into eq2
\n" ); document.write( "L-6=(900/L)+5 multiply each term by L
\n" ); document.write( "L^2-6L=900+5L put the quadratic in standard form
\n" ); document.write( "L^2-11L-900=0 and this can be factored
\n" ); document.write( "(L+25)(L-36)=0
\n" ); document.write( "L=-25m-----------------------------no good lengths are positive
\n" ); document.write( "L=36m----Length of rectangle
\n" ); document.write( "Substitute into eq1, we get W=25m---Width of rectangle
\n" ); document.write( "Perimeter would be 2*36+2*25=122m\r
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\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "36-6=30
\n" ); document.write( "25+5=30
\n" ); document.write( "36*25=900\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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