document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756947>Question 756947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 200. The ratio of the first to the second is 5:6 and that of the second to the third is 2:3<BR>\n" );
document.write( "What is the difference between the largest and the smallest number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460521 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the three numbers be a,b,c<BR>\n" );
document.write( "Sum: a + b + c = 200<BR>\n" );
document.write( "Ratios: a/b = 5/6; b/c = 2/3 -> c/b = 3/2<BR>\n" );
document.write( "Dividing the first equation by b gives:<BR>\n" );
document.write( "a/b + 1 + c/b = 200/b<BR>\n" );
document.write( "Substituting and solving for b gives:<BR>\n" );
document.write( "5/6 + 1 + 3/2 = 200/b<BR>\n" );
document.write( "20/6 = 200/b<BR>\n" );
document.write( "b = 60<BR>\n" );
document.write( "Therefore a = 5/6(60) = 50; c = 3/2(60) = 90<BR>\n" );
document.write( "Ans: 50,60,90<BR>\n" );
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