document.write( "Question 756894: 5(x+4)=20 \n" ); document.write( "
Algebra.Com's Answer #460500 by lenny460(1073)\"\" \"About 
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5(x+4) = 20\r
\n" ); document.write( "\n" ); document.write( "5 * x = 5x\r
\n" ); document.write( "\n" ); document.write( "5 * 4 = 20\r
\n" ); document.write( "\n" ); document.write( "Therefore we now have:\r
\n" ); document.write( "\n" ); document.write( "5x + 20 = 20\r
\n" ); document.write( "\n" ); document.write( "Subtract 20 from each side of the equation.\r
\n" ); document.write( "\n" ); document.write( "5x + 20 - 20 = 20 - 20\r
\n" ); document.write( "\n" ); document.write( "5x = 0\r
\n" ); document.write( "\n" ); document.write( "Divide each side by 5\r
\n" ); document.write( "\n" ); document.write( "x = 0\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "x = 0\r
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\n" ); document.write( "\n" ); document.write( "Lennox Obuong
\n" ); document.write( "Algebra Tutor
\n" ); document.write( "Nairobi, Kenya
\n" ); document.write( "Email: obuong3@aol.com
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