document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756870>Question 756870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an isosceles triangle has an area of 48 ft squared. If the base is 12 ft what is the length of each leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460496 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of the isoceles triangle=1/2 base*altitude<BR>\n" );
document.write( "base=12 & area=48<BR>\n" );
document.write( "so altitude=48*2/12=8<BR>\n" );
document.write( "now the altitude divides the triangle into two right angled triangles<BR>\n" );
document.write( "so each leg of the trianle=sq root [(altitude)^2+(1/2base)^2]<BR>\n" );
document.write( "=sq root [(8)^2+(1/2*12)^2]=sq root [64+36]=sq root 100=10<BR>\n" );
document.write( " </SPAN>\n" );
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