document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756905>Question 756905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One morning, John drove 11 hours before stopping to eat. After lunch, he increased his speed by 10 mph. If he completed a 590-mile trip in 14 hours of driving time, how fast did he drive in the morning? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460487 by </B><A HREF=/tutors/aboutme.mpl?userid=Nihal@SriLanka><B>Nihal@SriLanka(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nihal@SriLanka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming morning drive speed was x mph John has driven 11 hrs at speed x and 3 hours at speed (x+10).\r<BR>\n" );
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document.write( "Hence forming equation for total distance driven, we have<BR>\n" );
document.write( "x.11 + (x+10).3 = 590<BR>\n" );
document.write( "i.e. 11x +3x +30= 590<BR>\n" );
document.write( "i.e. 14x +30 -30= 590 -30<BR>\n" );
document.write( "i.e. 14x        = 560<BR>\n" );
document.write( "i.e.   x        = 560/14 = 40 mph  </SPAN>\n" );
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