document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756919>Question 756919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers are such that the ratio between them is 3:5. If each is increased by 10, the ratio between the new numbers so formed is 5:7. Find the original numbers. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460473 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Equation 1:  x/y = 3/5<P><BR>\n" );
document.write( "5x = 3y<P><BR>\n" );
document.write( "x = 3y/5<P><BR>\n" );
document.write( "Equation 2:(x+10)/(y+10) = 5/7<P><BR>\n" );
document.write( "7(x+10) =5(y+10)<P><BR>\n" );
document.write( "7x + 70 = 5y + 50<P><BR>\n" );
document.write( "Substitute in the value of x from equation 1.<P><BR>\n" );
document.write( "7(3y/5) + 70 = 5y + 50<P><BR>\n" );
document.write( "21y/5 + 70 = 5y + 50<P><BR>\n" );
document.write( "20 = 5y - 21y/5<P><BR>\n" );
document.write( "20 = 25y/5 - 21y/5 = 4y/5<P><BR>\n" );
document.write( "100 = 4y<P><BR>\n" );
document.write( "25 = y<P><BR>\n" );
document.write( "Substitute that back into equation 1:  x = 3*25/5 = 75/5 = 15 </SPAN>\n" );
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