document.write( "Question 756872: form a polynomial with real coefficients of degree 2 so that 2+2i is zero \n" ); document.write( "

Algebra.Com's Answer #460456 by josgarithmetic(39618) $\"\"$ $\"About$

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Degree of 2, possible two zeros, and you must expect the conjugate of your given zero is also a zero. Your TWO zeros are 2+2i AND 2-2i.\r
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\n" ); document.write( "\n" ); document.write( "Equation is $\"%28x-%282%2B2i%29%29%28x-%282-2i%29%29=0\"$
\n" ); document.write( " $\"%28x-2-2i%29%28x-2%2B2i%29=0\"$
\n" ); document.write( " $\"%28%28x-2%29-2i%29%28%28x-2%29%2B2i%29=0\"$
\n" ); document.write( "THE MULTIPLICATION GIVES DIFFERENCE OF TWO SQUARES
\n" ); document.write( " $\"%28x-2%29%5E2-%282i%29%5E2=0\"$
\n" ); document.write( " $\"x%5E2-4x%2B4-4%2A%28-1%29=0\"$
\n" ); document.write( " $\"x%5E2-4x%2B4%2B4=0\"$
\n" ); document.write( " $\"highlight%28x%5E2-4x%2B8=0%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "EDITED: Corrected mistake.\r
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