document.write( "Question 756789: Could you please help me with this algebra problem:
\n" ); document.write( "Sailing time. A boat sails a distance of 440 nautical miles. If the boat had averaged 11 nautical miles more each day, the trip would have required 2 fewer days. How long did the trip take?
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Algebra.Com's Answer #460440 by ankor@dixie-net.com(22740)\"\" \"About 
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A boat sails a distance of 440 nautical miles.
\n" ); document.write( " If the boat had averaged 11 nautical miles more each day,
\n" ); document.write( "the trip would have required 2 fewer days.
\n" ); document.write( " How long did the trip take?
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\n" ); document.write( "Let s = Actual number of miles per day traveled
\n" ); document.write( "then
\n" ); document.write( "(s+11) = Faster speed of the boat, covering 11 more miles per day
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\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "Actual time - faster time = 2 days
\n" ); document.write( "\"440%2Fs\" - \"440%2F%28%28s%2B11%29%29\" = 2
\n" ); document.write( "Multiply by s(s+11) to cancel the denominators, resulting in:
\n" ); document.write( "440(s+11) - 440s = 2s(s+11)
\n" ); document.write( "440s + 4840 - 440s = 2s^2 + 22s
\n" ); document.write( "Form a quadratic equation on the right
\n" ); document.write( "0 = 2s^2 + 22s - 4840
\n" ); document.write( "Simplify divide by 2
\n" ); document.write( "s^2 + 11s - 2420 = 0
\n" ); document.write( "Factors
\n" ); document.write( "(s+55)(s-44) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "s = 44 miles per day the normal speed
\n" ); document.write( ":
\n" ); document.write( " How long did the trip take?
\n" ); document.write( "\"440%2F44\" = 10 days
\n" ); document.write( ":
\n" ); document.write( "Check solution using the faster speed (+11 = 55)
\n" ); document.write( "\"440%2F55\" = 8 days, 2 less\r
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