document.write( "Question 756798: How do I find the real zero of a polynomial function fx=-9(x-8)(x-1).
\n" ); document.write( "I put it in my calculator and it solved the problem for -72. But I do not know the amount of real zeros or how to find them if there are any.
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Algebra.Com's Answer #460434 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"fx=-9%28x-8%29%28x-1%29\"$ .....to find the real zero of a polynomial function set $\"f%28x%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"-9%28x-8%29%28x-1%29=0\"$ ...since you have $\"f%28x%29\"$ completely factored, use zero product rule to find solutions\r
\n" ); document.write( "\n" ); document.write( " $\"-9%28x-8%29%28x-1%29=0\"$ ...since $\"-9%3C%3E0\"$ , the product will be equal to zero if $\"%28x-8%29=0\"$ or $\"%28x-1%29=0\"$ \r
\n" ); document.write( "\n" ); document.write( "if $\"%28x-8%29=0\"$ => $\"highlight%28x=8%29\"$ \r
\n" ); document.write( "\n" ); document.write( "if $\"%28x-1%29=0\"$ => $\"highlight%28x=1%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so, you have two real zeros\r
\n" ); document.write( "\n" ); document.write( "let see them on a graph:\r
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