document.write( "Question 65498This question is from textbook Essential Algebra
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document.write( ": Abigail Nightwind has planned a bike trip with some friends from her village. They will bike for 8 hours, then hike for 4 hours. If they can bike on the average 10mph fater than they can hike and if they will cover a total of 122 miles, how fast can Abigail and her friends bike? \n" );
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Algebra.Com's Answer #46041 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Abigail Nightwind has planned a bike trip with some friends from her village. They will bike for 8 hours, then hike for 4 hours. If they can bike on the average 10mph faster than they can hike and if they will cover a total of 122 miles, how fast can Abigail and her friends bike? \n" ); document.write( "The formula for distance is: \n" ); document.write( "Givens for the hike protion: \n" ); document.write( "t=4 \n" ); document.write( "r=r (we don't know it) \n" ); document.write( "d=4r \n" ); document.write( "Givens for the bike protion: \n" ); document.write( "t=8 \n" ); document.write( "r=r+10 (10 mph faster than they can hike.) \n" ); document.write( "d=8(r+10) \n" ); document.write( "The total of the trip= 122 \n" ); document.write( "Problem to solve: \n" ); document.write( "4r+8(r+10)=122 \n" ); document.write( "4r+8r+80=122 \n" ); document.write( "12r+80=122 \n" ); document.write( "12r+80-80=122-80 \n" ); document.write( "12r=42 \n" ); document.write( "12r/12=42/12 \n" ); document.write( "r=3.5 \n" ); document.write( "Therefore the rate that they can bike: r+10=3.5+10=13.5 mph \n" ); document.write( ": \n" ); document.write( "Sanity check: \n" ); document.write( "If they hiked for 4 hrs at 3.5 mph and biked for 8 hrs at 13.5 mph, would they travel 122 mi? \n" ); document.write( "4(3.5)+8(13.5)=122 ? \n" ); document.write( "14+108=122 \n" ); document.write( "122=122 It appears we are sane. \n" ); document.write( "Happy Calculating!!!! \n" ); document.write( " |