document.write( "Question 756700: sum of 3 digits number 24. square 224 \n" ); document.write( "
Algebra.Com's Answer #460378 by dkppathak(439)\"\" \"About 
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let numbers are
\n" ); document.write( "a-d ,a, a+d
\n" ); document.write( "as per given conditions sum is 24
\n" ); document.write( "a-d+a+a+d=24
\n" ); document.write( "3a=24
\n" ); document.write( "a=8
\n" ); document.write( "as per second conditions
\n" ); document.write( "(a-d)^2 +a^2 +(a+d)^2=224
\n" ); document.write( "a^2+d^2-2ad+a^2+a^2+d^2-2ad=224
\n" ); document.write( "3a^2+2d^2=224
\n" ); document.write( "putting a=8
\n" ); document.write( "we will get
\n" ); document.write( "3x(8)^2+2d^2=224
\n" ); document.write( "2d^2=224-192
\n" ); document.write( "2d^2=32
\n" ); document.write( "d^2=16
\n" ); document.write( "d=4
\n" ); document.write( "numbers will be a-d=8-4=4
\n" ); document.write( " a=8
\n" ); document.write( " a+d=8+4=12
\n" ); document.write( "ANSWER
\n" ); document.write( "4,8,12
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