document.write( "Question 756700: sum of 3 digits number 24. square 224 \n" ); document.write( "
Algebra.Com's Answer #460378 by dkppathak(439) You can put this solution on YOUR website! let numbers are \n" ); document.write( "a-d ,a, a+d \n" ); document.write( "as per given conditions sum is 24 \n" ); document.write( "a-d+a+a+d=24 \n" ); document.write( "3a=24 \n" ); document.write( "a=8 \n" ); document.write( "as per second conditions \n" ); document.write( "(a-d)^2 +a^2 +(a+d)^2=224 \n" ); document.write( "a^2+d^2-2ad+a^2+a^2+d^2-2ad=224 \n" ); document.write( "3a^2+2d^2=224 \n" ); document.write( "putting a=8 \n" ); document.write( "we will get \n" ); document.write( "3x(8)^2+2d^2=224 \n" ); document.write( "2d^2=224-192 \n" ); document.write( "2d^2=32 \n" ); document.write( "d^2=16 \n" ); document.write( "d=4 \n" ); document.write( "numbers will be a-d=8-4=4 \n" ); document.write( " a=8 \n" ); document.write( " a+d=8+4=12 \n" ); document.write( "ANSWER \n" ); document.write( "4,8,12 \n" ); document.write( " |