document.write( "Question 756556: 13) Write the equation for a hyperbola with the following:
\n" ); document.write( "a. foci at (±5, 7) and vertices at (±3, 7)
\n" ); document.write( "b. a horizontal transverse axis, a = 5 and c = 13
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Algebra.Com's Answer #460305 by lwsshak3(11628)\"\" \"About 
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Write the equation for a hyperbola with the following:
\n" ); document.write( "a. foci at (±5, 7) and vertices at (±3, 7)
\n" ); document.write( "Given hyperbola has a horizontal transverse axis.
\n" ); document.write( "Its standard form of equation: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center
\n" ); document.write( "y-coordinate of center=7
\n" ); document.write( "x-coordinate of center=0 (midpoint of vertices or foci)
\n" ); document.write( "center:(0,7)
\n" ); document.write( "a=3 (distance from center to vertices)
\n" ); document.write( "a^2=9
\n" ); document.write( "c=5 (distance from center to foci)
\n" ); document.write( "c^2=25
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "b^2=c^2-a^2=25-9=16
\n" ); document.write( "Equation of given hyperbola:
\n" ); document.write( "\"x%5E2%2F9-%28y-7%29%5E2%2F16=1\"
\n" ); document.write( "..
\n" ); document.write( "b. a horizontal transverse axis, a = 5 and c = 13
\n" ); document.write( "b^2=c^2-a^2=169-25=144
\n" ); document.write( "center not given, assume (0,0)
\n" ); document.write( "Equation:\"x%5E2%2F25-y%5E2%2F144=1\"
\n" ); document.write( "
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