document.write( "Question 65490: (92) Statistics. Sam must have an average of 70 or more in his summer course to obtain a grade of C. His first three test grades were 75,63, and 68. Write an inequality representing the score that Sam must get on the last test to get a C grade.\r
\n" ); document.write( "\n" ); document.write( "(94) Business and finance. The cost for a long-distance telephone call is $0.36 for the first minute and $0.21 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding $3.\r
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Algebra.Com's Answer #46022 by venugopalramana(3286)\"\" \"About 
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(92) Statistics. Sam must have an average of 70 or more in his summer course to obtain a grade of C. His first three test grades were 75,63, and 68. Write an inequality representing the score that Sam must get on the last test to get a C grade.
\n" ); document.write( "TOTAL MARKS IN 3 TESTS = 75+63+68=206
\n" ); document.write( "LET SCORE IN THE LAST TEST = X
\n" ); document.write( "TOTAL SCORE IN 4 TESTS = 206+X
\n" ); document.write( "AVERAGE IN 4 TESTS = A = (206+X)/4
\n" ); document.write( "A>=70 HENCE
\n" ); document.write( "(206+X)/4 >=70
\n" ); document.write( "206+X >= 4*70=280
\n" ); document.write( "X>= 280-206=74\r
\n" ); document.write( "\n" ); document.write( "(94) Business and finance. The cost for a long-distance telephone call is $0.36 for the first minute and $0.21 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding $3.
\n" ); document.write( "L.D.CALL CHARGE FOR 1 ST.MINUTE = 0.36
\n" ); document.write( "LET THE TOTAL NUMBER OF MINUTES TALKED = T MTS.
\n" ); document.write( "ADDITIONAL MINUTES TALKED OVER THE I MINUTE = T-1
\n" ); document.write( "CHARGES FORT ADDITIONAL MINUTES = (T-1)*0.21
\n" ); document.write( "TOTAL CHARGE = 0.36+(T-1)*0.21<=3.00 $
\n" ); document.write( "0.36+0.21T-0.21<=3
\n" ); document.write( "0.21T<=3-0.36+0.21=2.85
\n" ); document.write( "T<=2.85/0.21=285/21=95/7.\r
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