document.write( "Question 755989: if tan theta= -13/12 where theta is in 2nd quadrant find remaing trigonometric ratios \n" ); document.write( "
Algebra.Com's Answer #460199 by priyanka kothandaraman(2)\"\" \"About 
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\n" ); document.write( "tan theta = sin theta/cos theta
\n" ); document.write( "So \r
\n" ); document.write( "\n" ); document.write( " sin/cos=-13/12
\n" ); document.write( "12sin theta=-13cos theta
\n" ); document.write( "144sin^2theta=169^2theta
\n" ); document.write( "but,
\n" ); document.write( " cos^2theta=1-sin^2theta
\n" ); document.write( "144sin^2theta=169-169sin^2theta
\n" ); document.write( "sin theta=169/313
\n" ); document.write( "sin theta=13/root313
\n" ); document.write( "=13root313/313 \r
\n" ); document.write( "\n" ); document.write( "Note: save the unrationalized denominator form for ease of taking the reciprocal later. \r
\n" ); document.write( "\n" ); document.write( "Do in the same fashion giving you three of the six functions. Then, the other functions are just reciprocals: \r
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