document.write( "Question 756387: the second of three consecutive odd numbers diminished by twice the third and increased by 16 gives a value that is three times that of the first number diminished by 2. I need help figuring out what the integers are. \n" ); document.write( "
Algebra.Com's Answer #460168 by rothauserc(4718)\"\" \"About 
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Let x be our first odd integer, then x+2 and x+4 are the second and third consecutive odd integers.\r
\n" ); document.write( "\n" ); document.write( "now from the word problem we can write\r
\n" ); document.write( "\n" ); document.write( "3x -2 = (x+2) -2*(x+4)+16
\n" ); document.write( "3x -2 = x+2 -2x-8 +16
\n" ); document.write( "3x = x+4 -2x-8 +16
\n" ); document.write( "3x = -x +12
\n" ); document.write( "4x = 12
\n" ); document.write( "x=3\r
\n" ); document.write( "\n" ); document.write( "so our three consecutive odd integers are 3, 5, 7\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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