document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756376>Question 756376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what equation is perpendicular to the line that passes through the points (-2,-1) and (7,-4)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460164 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope of the line through (-2,-1) and (7,-4) is...\r<BR>\n" );
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document.write( "m = (y2-y1)/(x2-x1)\r<BR>\n" );
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document.write( "m = (-4-(-1))/(7-(-2))\r<BR>\n" );
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document.write( "m = (-4+1)/(7+2)\r<BR>\n" );
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document.write( "m = (-3)/9\r<BR>\n" );
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document.write( "m = -1/3\r<BR>\n" );
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document.write( "The perpendicular slope is 3/1 = 3 (flip the fraction and flip the sign)\r<BR>\n" );
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document.write( "So any equation with a slope of 3 will be perpendicular to this line.\r<BR>\n" );
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document.write( "So the equation might be y = 3x + 2 or y = 3x + 5 </SPAN>\n" );
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