document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756348>Question 756348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many tons of dirt would this be?\r<BR>\n" );
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document.write( "210 feet long by 90 feet wide by 14 feet deep </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460158 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The description is not complete but just know there would be a value D pounds per cubic feet for the \"dirt\".  You have a volume description and if you have the density D, then you can find the \"pounds\" of this volume of dirt.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28210%2A90%2A14%29%28ft%2Aft%2Aft%29%2AD%28pounds%2F%28ft%2Aft%2Aft%29%29 ALIGN=MIDDLE  ALT=\"%28210%2A90%2A14%29%28ft%2Aft%2Aft%29%2AD%28pounds%2F%28ft%2Aft%2Aft%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28210%2A90%2A14%2AD%29%2A%28pounds%29 ALIGN=MIDDLE  ALT=\"%28210%2A90%2A14%2AD%29%2A%28pounds%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You would need to know the value of D if you want the value of pounds for this dirt. </SPAN>\n" );
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