document.write( "Question 756295: paula can do a plumbing job in 3 hours if maria and paula can complete a job in 2 hours how long would it take maria, working alone,to complete the job? \n" ); document.write( "
Algebra.Com's Answer #460084 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time it takes Maria working alone to complete the job \n" ); document.write( "Then maria works at the rate of 1/x of the job per hour \n" ); document.write( "Paula works at the rate of 1/3 of the job per hour \n" ); document.write( "Maria and Paula together work at the rate of 1/2 of the job per hour \n" ); document.write( "Sooooo, our equation to solve is: \n" ); document.write( "1/x+1/3=1/2 multiply each term by 6x \n" ); document.write( "6+2x=3x subtract 2x from each side \n" ); document.write( "x=6 hours----time it takes Maria working alone to complete the job\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "In 2 hours, Paula completes 2/3 of the job, leaving 1/3 to be done \n" ); document.write( "In 2 hours, Maria completes 2/6=1/3 of the job \n" ); document.write( "1/3+2/3=The Job\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |