document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756295>Question 756295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> paula can do a plumbing job in 3 hours if maria and paula can complete a job in 2 hours how long would it take maria, working alone,to complete the job? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460081 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Maria can do job in 2 hours<BR>\n" );
document.write( "Paula can do the job in 3 hours<BR>\n" );
document.write( "Maria's rate 1/3rd of a job in an hour<BR>\n" );
document.write( "Paula's rate 1/2   of a job in an hour\r<BR>\n" );
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document.write( " Therefore 1/3 + 1/2 = 1/x\r<BR>\n" );
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document.write( "Taking the common denominator of 6x\r<BR>\n" );
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document.write( "            2x + 3x = 6<BR>\n" );
document.write( "                 5x = 6<BR>\n" );
document.write( "                  x = 6/5 = 1 1/5 hours<BR>\n" );
document.write( "   or 1 hour 12 mins (1/5 of 60)<BR>\n" );
document.write( "Hope this helps<BR>\n" );
document.write( ":-) </SPAN>\n" );
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