document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756264>Question 756264</A>: <I><SPAN STYLE=\"word-break: break-all;\">  two vehicles set off from same point for the same journey. Vehicle A travels at 50km/h. Vehicle B leaves after 9 mins and travels 55 km/h. At what distance will A & B be level? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460071 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let after t min & s m both meet<BR>\n" );
document.write( "then A travels for t min & the distance=50*50*t/3 m <BR>\n" );
document.write( "[as 1km/hr=50/3m/min]<BR>\n" );
document.write( "& B travels for t-9 min & moves a distance= 55*50(t-9)/3 m<BR>\n" );
document.write( "now 50*50*t/3=55*50(t-9)/3<BR>\n" );
document.write( "or 50t=55(t-9)=55t-55*9<BR>\n" );
document.write( "or 5t=55*9<BR>\n" );
document.write( "or t=11*9=99 min<BR>\n" );
document.write( "so the distance=50*50*t/3=50*50*99/3=82500m=82.5 km </SPAN>\n" );
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