document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=756231>Question 756231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not shore how do do this please help.<BR>\n" );
document.write( "Girl A leaves on a long trip driving at a rate of 45 miles per hour. Girl B leaves from the same location traveling to the same destination 2 hours later. Girl B drives at a steady rate of 55 miles per hour. How long after Girl B leaves home will Girl A catch up?\r<BR>\n" );
document.write( "\n" );
document.write( "I keep geting 10hours, but I dont think im right </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #460047 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=460047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Girl A leaves on a long trip driving at a rate of 45 miles per hour. Girl B leaves from the same location traveling to the same destination 2 hours later. Girl B drives at a steady rate of 55 miles per hour. How long after Girl B leaves home will Girl A catch up?<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "In 2 hours Girl A is 90 miles away (45*2).<BR>\n" );
document.write( "Girl B \"gains on her\" at 10 mi/hr (55-45).<BR>\n" );
document.write( "90/10 = 9 hours after Girl B leaves.<BR>\n" );
document.write( "============<BR>\n" );
document.write( "How long after Girl B leaves home will Girl A catch up?<BR>\n" );
document.write( "Girl B catches up. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );