document.write( "Question 756218: I really need help on this. Thanks so much. I would really appreciate it. \r
\n" ); document.write( "\n" ); document.write( "Final averages are typically approximately normally distributed with a mean of 78 and a standard deviation of 11. Your professor says that the top 6% of the class will receive an A; the next 24%, a B; the next 41%, a C; the next 18%, a D; and the bottom 11%, an F. (Give your answers correct to one decimal place.)\r
\n" ); document.write( "\n" ); document.write( "(a) What average must you exceed to obtain an A?\r
\n" ); document.write( "\n" ); document.write( "(b) What average must you exceed to receive a grade of C or better?\r
\n" ); document.write( "\n" ); document.write( "(c) What average must you obtain to pass the course? (You'll need a D or better.)\r
\n" ); document.write( "\n" ); document.write( "You may need to use the appropriate table in Appendix B to answer this question.
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Algebra.Com's Answer #460044 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Final averages are typically approximately normally distributed with a mean of 78 and a standard deviation of 11. Your professor says that the top 6% of the class will receive an A; the next 24%, a B; the next 41%, a C; the next 18%, a D; and the bottom 11%, an F. (Give your answers correct to one decimal place.)
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\n" ); document.write( "Using a TI-84 to get these answers.
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\n" ); document.write( "(a) What average must you exceed to obtain an A?
\n" ); document.write( "Find the z-value with a left-tail of 94%
\n" ); document.write( "invNorm(0.94) = 1.5548
\n" ); document.write( "Using the formula z = (x-u)/s to solve for \"x\"
\n" ); document.write( "you get x = z*s+u
\n" ); document.write( "x is the score; z, s, and u you now know.
\n" ); document.write( "So solve for \"x\":
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\n" ); document.write( "score = 1.5548*11+78 = 95.1
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\n" ); document.write( "(b) What average must you exceed to receive a grade of C or better?
\n" ); document.write( "invNorm(0.29) = -0.5534
\n" ); document.write( "score = -9.5534*11+78 = 71.91
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\n" ); document.write( "(c) What average must you obtain to pass the course? (You'll need a D or better.)
\n" ); document.write( "invNorm(-.11) = -1.2265
\n" ); document.write( "score = -1.2265*11+78 = 64.51
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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