document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65476>Question 65476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide the fraction:\r<BR>\n" );
document.write( "\n" );
document.write( "6p-18  /  3p-9<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "9p     /  p^2+2p\r<BR>\n" );
document.write( "\n" );
document.write( "The first step is to invert the second fraction I believe:\r<BR>\n" );
document.write( "\n" );
document.write( "6p-18  /  p^2+2p<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( " 9p        3p-9\r<BR>\n" );
document.write( "\n" );
document.write( "The next step is to cancel out I think:\r<BR>\n" );
document.write( "\n" );
document.write( "3 goes in to 6, 9, and 18 <BR>\n" );
document.write( "The last fraction has no cancel outs leaving the equation looking like this:<BR>\n" );
document.write( "2p-6  /  p^2+2p<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "  3p  /   3p-9\r<BR>\n" );
document.write( "\n" );
document.write( "From here I become preety lost. Is there any hope for me in figuring this problem out? I would be happy with a good break down for future reference as well so I could really figure them out. Thank you in advance for the great help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46004 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Divide the fraction:\r<BR>\n" );
document.write( "\n" );
document.write( "6p-18  /  3p-9<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "9p     /  p^2+2p\r<BR>\n" );
document.write( "\n" );
document.write( "==================<BR>\n" );
document.write( "Rewrite as follows:\r<BR>\n" );
document.write( "\n" );
document.write( "=[6(p-3)/3(p-3)] / [9p/p(p+2)]\r<BR>\n" );
document.write( "\n" );
document.write( "Cancel where you can to get:\r<BR>\n" );
document.write( "\n" );
document.write( "=2/[9/(p+2)]\r<BR>\n" );
document.write( "\n" );
document.write( "Invert the denominator and multiply to get:\r<BR>\n" );
document.write( "\n" );
document.write( "=(2/9)(p+2)\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );