document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65481>Question 65481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Subtract and express result in simplest form\r<BR>\n" );
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document.write( "5a - 12    -   3a - 2<BR>\n" );
document.write( "-------        -------<BR>\n" );
document.write( "a^2-8a+15  -   a^2-8a+15\r<BR>\n" );
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document.write( "The top part of the fraction I believe would end up looking like this:<BR>\n" );
document.write( "5a - 12 = -7a<BR>\n" );
document.write( "3a - 2 = 1a\r<BR>\n" );
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document.write( "The bottom part of the fraction would result in <BR>\n" );
document.write( "a^2-8a+15 = 23a^3\r<BR>\n" );
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document.write( "Leaving the equation ending with the result of:<BR>\n" );
document.write( "-7a   -   1a<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "23a^3      23a^3\r<BR>\n" );
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document.write( "Simplest form would be:<BR>\n" );
document.write( "-6a<BR>\n" );
document.write( "----<BR>\n" );
document.write( "23a^3\r<BR>\n" );
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document.write( "Is this correct for this problem? Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46002 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5a - 12    -   3a - 2<BR>\n" );
document.write( "-------        -------<BR>\n" );
document.write( "a^2-8a+15  -   a^2-8a+15\r<BR>\n" );
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document.write( "---------------------<BR>\n" );
document.write( "The denominators are the same so subtract the numerators <BR>\n" );
document.write( "and write over the common denominator, as follows:<BR>\n" );
document.write( "=[5a-12-(3a-2)]/[(a-3)(a-5)]<BR>\n" );
document.write( "=[2a-10]/[(a-3)(a-5)]<BR>\n" );
document.write( "=[2(a-5)]/[(a-3)(a-5)]<BR>\n" );
document.write( "=2/(a-3)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );